x^2+(4x)x(2-3i)=0

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Solution for x^2+(4x)x(2-3i)=0 equation: 


Simplifying
x2 + (4x) * x(2 + -3i) = 0

Remove parenthesis around (4x)
x2 + 4x * x(2 + -3i) = 0

Multiply x * x
x2 + 4x2(2 + -3i) = 0
x2 + (2 * 4x2 + -3i * 4x2) = 0

Reorder the terms:
x2 + (-12ix2 + 8x2) = 0
x2 + (-12ix2 + 8x2) = 0

Reorder the terms:
-12ix2 + x2 + 8x2 = 0

Combine like terms: x2 + 8x2 = 9x2
-12ix2 + 9x2 = 0

Solving
-12ix2 + 9x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9x2' to each side of the equation.
-12ix2 + 9x2 + -9x2 = 0 + -9x2

Combine like terms: 9x2 + -9x2 = 0
-12ix2 + 0 = 0 + -9x2
-12ix2 = 0 + -9x2
Remove the zero:
-12ix2 = -9x2

Divide each side by '-12x2'.
i = 0.75

Simplifying
i = 0.75

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